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In the given circuit,find the power dissipated in 6 ohm ressistance.(do not spam either will get reported) ANS-9 watt (need full process) |
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Answer» Given: A circuit has been provided. The voltage source is 20 V To find: Power dissipated in the 6 ohm resistor. Concept: First find out the equivalent resistance of the circuit. In that equivalent circuit , find out the current . Then the power dissipated can be easily calculated. Power is the amount of energy dissipated by the resistance per unit time. Calculation: See the diagram for simplified circuit. The 5 ohm, 4 ohm and 6 ohm are in series. So NET current will be : I = \dfrac{V}{(5 + 4 + 6)}I= (5+4+6) V
= > I = \dfrac{20}{(15)}=>I= (15) 20
= > I = \dfrac{4}{3} amp.=>I= 3 4
amp. Power dissipated in the 6 ohm resistor will be : P = {(I)}^{2} \times 6P=(I) 2 ×6 = > P = {( \dfrac{4}{3} )}^{2} \times 6=>P=( 3 4
) 2 ×6 = > P = \dfrac{16}{9} \times 6=>P= 9 16
×6 = > P = 10.66 \: WATT=>P=10.66watt So final answer : \huge{ \green{ \sf{ \bold{ P = 10.66 \: watt}}}}P=10.66watt |
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