In the formation of so2 and so3 the ratio of their weights of oxygen w

1.	In the formation of so2 and so3 the ratio of their weights of oxygen which combines with 10kg of sulphur is
Answer» The ratio of weights of OXYGEN = 2 : 3 Given , formation of SO2 and SO3 MASS of Sulphur = 10 kg Moles of Sulphur = 10 * 10^3 g /32 g/mol = 0.3125 * 10^3 moles Now the reactions involved are: S + O2 ⇒ SO2 , 2S + 3 O2 ⇒ 2SO3 Now ,it is clear 1 mole of S requires 1 mole of O2 to form 1 mole SO2 Also, 2 moles of S requires 3 moles of O2 to form 2 moles of SO3 So,*0.3125 10 ^3 moles of Sulphur combines with 0.3125 * 10^3 moles of Oxygen to from SO2. Also, 0.3125 * 10 ^3 moles of S combines with 0.3125 * 10^3 * 3/2 moles of Oxygen to form SO3 We KNOW, 1 mole of O2 = 32 GM of O2** 0.3125 * 10 ^3 mole of O2 = 10 * 10^3 gm of O2 0.3125 * 3/2 * 10^3 mole of O2 = 15 * 10^3 gm of O2 Therfore mass ratio of SO2 : SO3 = 10 : 15 = 2:3.

In the formation of so2 and so3 the ratio of their weights of oxygen which combines with 10kg of sulphur is

Answer»

The ratio of weights of OXYGEN = 2 : 3

Given , formation of SO2 and SO3
MASS of Sulphur = 10 kg
Moles of Sulphur = 10 * 10^3 g /32 g/mol = 0.3125 * 10^3 moles
Now the reactions involved are: S + O2 ⇒ SO2 , 2S + 3 O2 ⇒ 2SO3
Now ,it is clear 1 mole of S requires 1 mole of O2 to form 1 mole SO2
Also, 2 moles of S requires 3 moles of O2 to form 2 moles of SO3
So,0.3125 * 10 ^3 moles of Sulphur combines with 0.3125 * 10^3 moles of Oxygen to from SO2.
Also, 0.3125 * 10 ^3 moles of S combines with 0.3125 * 10^3 * 3/2 moles of Oxygen to form SO3
We KNOW, 1 mole of O2 = 32 GM of O2
0.3125 * 10 ^3 mole of O2 = 10 * 10^3 gm of O2
0.3125 * 3/2 * 10^3 mole of O2 = 15 * 10^3 gm of O2
Therfore mass ratio of SO2 : SO3 = 10 : 15 = 2:3.