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In the following table, six elements A, B, C, D, E and F (here letters are not the usual symbols of the elements) of the modern Periodic Table with atomic numbers 3 to 18 are given:345678910AEG1112131415161718BCDF(a) Which of these is (i) a noble gas, (ii) a halogen? (b) If B combines with F, what would be the formula of the compound formed? (c) Write the electronic configurations of C and E. |
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Answer» (a) (i) G with atomic number 10 is a noble gas because it has complete octet. (ii) F with atomic number 17 is a halogen. (b) B with atomic number 11 has 1 valence electron and F with atomic number 17 has 7 valence electrons so the formula of the compound formed would be BF. (c) Electronic configuration of C and E are E8- 2, 6 C12- 2, 8, 2 |
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