1.

In the following figure, O is the centre of the circle. AB is an arc of the circle, such that `angle AOB=80^@`.Find `angle ACB`.

Answer» The angle made by an arc at the centre of a circle is twice the angle made by the arc at any point on the remaining part of the circle.
`angle AOB=2angleACB`
`rArr2angle ACB =80^@`
`rArr angle ACB =40^@`.


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