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In the following figure, O is the centre of the circle. AB is an arc of the circle, such that `angle AOB=80^@`.Find `angle ACB`. |
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Answer» The angle made by an arc at the centre of a circle is twice the angle made by the arc at any point on the remaining part of the circle. `angle AOB=2angleACB` `rArr2angle ACB =80^@` `rArr angle ACB =40^@`. |
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