In the following chain reaction, A → B → C, A and B are radioactiv

1.	In the following chain reaction, A → B → C, A and B are radioactive while C is stable. Initially we have only A and B type of nuclei. There is no nucleus of type C. As the time progresses, match the two columns Column IColumn II(A) Number of nuclei of (A +B)(p) Will increase continuously(B) Number of nuclei of (B)(q) Will decrease continuously(C) Number of nuclei of (C +B)(r) Will first increase and then decrease(D) Number of nuclei of (A +C)(s) Data insufficient
Answer» In the following chain reaction, A $\to$ B $\to$ C, A and B are radioactive while C is stable. Initially we have only A and B type of nuclei. There is no nucleus of type C. As the time progresses, match the two columns $\begin{matrix} Column I & Column II (A) Number of nuclei of (A +B) & (p) Will increase continuously (B) Number of nuclei of (B) & (q) Will decrease continuously (C) Number of nuclei of (C +B) & (r) Will first increase and then decrease (D) Number of nuclei of (A +C) & (s) Data insufficient \end{matrix}$

In the following chain reaction, A → B → C, A and B are radioactive while C is stable. Initially we have only A and B type of nuclei. There is no nucleus of type C. As the time progresses, match the two columns Column IColumn II(A) Number of nuclei of (A +B)(p) Will increase continuously(B) Number of nuclei of (B)(q) Will decrease continuously(C) Number of nuclei of (C +B)(r) Will first increase and then decrease(D) Number of nuclei of (A +C)(s) Data insufficient

Answer»

In the following chain reaction,

A $\to$ B $\to$ C, A and B are radioactive while C is stable. Initially we have only A and B type of nuclei. There is no nucleus of type C. As the time progresses, match the two columns

$\begin{matrix} Column I & Column II (A) Number of nuclei of (A +B) & (p) Will increase continuously (B) Number of nuclei of (B) & (q) Will decrease continuously (C) Number of nuclei of (C +B) & (r) Will first increase and then decrease (D) Number of nuclei of (A +C) & (s) Data insufficient \end{matrix}$

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