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In the figure, what is the magnetic field at the point `O`? A. `(mu_(0)l)/(4pir)`B. `(mu_(0)l)/(4r)+(mu_(0)l)/(2pir)`C. `(mu_(0)l)/(4r)+(mu_(0)l)/(4pir)`D. `(mu_(0)l)/(4r)-(mu_(0)l)/(4pir)` |
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Answer» Correct Answer - c Magnetic field due to stright wire above O is zero i.e `B_(1)=0(since,theta=0^(@))` The magnetic field due to semi circular part `B_(2)=(mu_(0)nI)/(2r)=(mu_(0)(1//2)I)/(2r)=(mu_(0)I)/(4r)` The magnetic field due to lower straight portion `B_(3)=(1)/(2)(mu_(0)I)/(2pir)(upward)` Net magnetic field `B=B_(1)+B_(2)+B_(3)` `=0+(mu_(0)I)/(4r)+(mu_(0)I)/(4pir)(upwards)` |
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