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| 1. |
In the figure shown, the two projectiles are fired simultaneously. The minimum distance between them during their flight is |
| Answer» STION is incomplete and here is the missing diagram in attachmentminimum distance is 10 m.Explanation:Taking the reference point at A and X- axis ALONG the AB line.The velocity of second projectile with respect to the first is given by velocity of first projectile-velocity of second projectile.The velocity of first projectile(A) is = 20√3(cos60î+sin60j)the velocity of second projectile(B) is =20(cos150î+sin150j)velocity of B with respect to A is = =20√3î+20jassume a third PARTICLE is moving with this velocity, this implies it is projected with an angle Ф=tan⁻¹ therefore, it is projected at an angle of 30°.minimum distance between the TWO projectiles is when their paths are particular. therefore they are PERPENDICULAR when this Ф=30°.from the below triangle in second figure, minimum distance is Therefore, | |