Saved Bookmarks
| 1. |
In the figure shown the key is switched on at `t=0`. Let `l_1` and `l_2` be the currents through inductors having self inductances `L_1` and `L_2` at any time t respectively. The magnetic energy stored in the inductors 1 and 2 be `U_1` and `U_2`. Then `U_1/U_2` at any instant of time is: A. `(L_(1))/(L_(2))`B. `(L_(2))/(L_(1))`C. `(I_(1))/(I_(2))`D. `(I_(2))/(I_(1))` |
|
Answer» Because both inductors are in parallel `:. L_(1)I_(1)=L_(2)I_(2)` `(U_(1))/(U_(2))=(1//2 L_(1)I_(1)I_(1))/(1//2L_(2)I_(2)I_(2))=(I_(1))/(I_(2))=(L_(2))/(L_(1))` |
|