In the figure shown as uniform magnetic field `|B|=0.5T` is perpendicular to the plane of circuit. The sliding rod of length `l=0.25 m` moves uniformly with constant speed `v=4ms^-1`. If the resistance of the sllides is `2Omega`, then the current flowing through the sliding rod is A. `0.1A`B. `0.17A`C. `0.08`D. `0.03A`

In the figure shown as uniform magnetic field `|B|=0.5T` is perpendicu

1.	In the figure shown as uniform magnetic field `\|B\|=0.5T` is perpendicular to the plane of circuit. The sliding rod of length `l=0.25 m` moves uniformly with constant speed `v=4ms^-1`. If the resistance of the sllides is `2Omega`, then the current flowing through the sliding rod is A. `0.1A`B. `0.17A`C. `0.08`D. `0.03A`
Answer» Correct Answer - A `e=Bvl=0.5xx4xx0.25=0.5V` `12Omega` and `4Omega` are parallel.Hence, their net resistance `R=3Omega` `i=e/(R+r)=0.5/(32)=0.1A`

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