Saved Bookmarks
| 1. |
in the figure seg BD perpendicular to seg AC. Angle C=30°angle A=45°BD=20cm.Find angke DBA ,ANGLE DBC SEG BC AND SEG DC |
|
Answer» Answer:Given: BD perpendicular to SIDE AC ( BD⊥AC) and DE perpendicular to side BC ( DE⊥BC) To prove: DExBD=DCxBE Proof: In \triangle BED\text{ and }\triangle BDC△BED and △BDC \angle BED=\angle BDC∠BED=∠BDC (Each 90° ) \angle DBE=\angle DBC∠DBE=∠DBC (Common in both triangle) So, \triangle BED \sim \triangle BDC△BED∼△BDC by AA similarity If two TRIANGLES are similar then their corresponding sides are in proportional. \dfrac{DE}{DC}=\dfrac{BE}{BD}DCDE=BDBE Using cross multiply DExBD=DCxBE Hence Proved plz MARK as brainliast answer Step-by-step explanation: |
|