In the figure, rays OA, OB, OC, OD and OE have the common end point O.

1.	In the figure, rays OA, OB, OC, OD and OE have the common end point O. Show that ∠AOB+∠BOC+∠COD+∠DOE+∠EOA=360∘.
Answer» In the figure, rays OA, OB, OC, OD and OE have the common end point O. Show that $∠ A O B + ∠ B O C + ∠ C O D + ∠ D O E + ∠ E O A = 360^{\circ}$ .

In the figure, rays OA, OB, OC, OD and OE have the common end point O. Show that ∠AOB+∠BOC+∠COD+∠DOE+∠EOA=360∘.

Answer»

In the figure, rays OA, OB, OC, OD and OE have the common end point O. Show that $∠ A O B + ∠ B O C + ∠ C O D + ∠ D O E + ∠ E O A = 360^{\circ}$ .