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In the figure, radius of the circle centered at O is 9 cm. OA = 15 cm. Semicircle with diameter O A cuts the circle with center O at D and BC is a tangent through B.1. What is the length of BC?2. If the line PD is perpendicular to OA, then what is the length of PD? |
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Answer» 1. BC2 = OB × BA = 9 × 6 = 54 BC = √54 cm 2. OP × OA = r2 \(OP=\frac{9^2}{15}=\frac{81}{15}\) PD2 = OP x PA \(PD^2=\frac{81}{15}\times\frac{144}{15}\) \(PD=\frac{9\times12}{15}=\frac{36}{5}=7.2\) cm |
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