1.

In the figure, pulleys are smooth and strings are massless, m_(1)=1 kg and m_(2)=(1)/(3)kg. To keep m_(3) at rest, mass m_(3) should be

Answer»

1 kg
`(2)/(3)kg`
`(1)/(4) kg`
`2 kg`

Solution :(a) `m_(3)` is at rest, Therefore

2T`=m_(3)g`….(i)
Further if `m_(3)` is at rest, then pully P is also at rest. Writing equations of motion.
`m_(1)g-T=m_(1)a` ….(II)
`T-m_(2)g=m_(2)a` ...(iii)
Solving Eq. (ii) and (iii) we GET, `m_(3)=1 kg `


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