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In the figure PA, PB and RS are the three tangents to the circle. Prove that the perimeter of ΔPRS is the sum of the lengths PA and PB. |
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Answer» PA = PB (Tangents from an outside point are equal) RA = RT ST = SB Perimeter of ΔPRS = PR + RS + PS = PR + (RT + ST) + PS = (PR + RA) + (SB + PS) (Since RT = RA, ST= SB) = PA + PB |
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