In the figure, O' is the centre of the circle.ZAOB = 100find /ADB. /°

1.	In the figure, O' is the centre of the circle.ZAOB = 100find /ADB. /°了100°
Answer» Angle AOB=100angle ACB=50 (angle made at centre is double the angle made at any other point) now,ACBD is a cyclic quadrilateral , so angle ADB + angle ACB=180 ( sum of opposite angles of a cyclic quad. is 180) therefore,angle ADB=180-50=130

In the figure, O' is the centre of the circle.ZAOB = 100find /ADB. /°了100°

Answer»

Angle AOB=100angle ACB=50 (angle made at centre is double the angle made at any other point)

now,ACBD is a cyclic quadrilateral , so angle ADB + angle ACB=180 ( sum of opposite angles of a cyclic quad. is 180)

therefore,angle ADB=180-50=130