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In the figure, chord AB `~= ` chord CD Prove that , ar AC `~=` arc BD |
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Answer» Chord `AB ~=` chord CD ….(Given ) `:.` Arc ACB `~=` arc CBD …(Arcs corresponding to congruent chords ) `:.` m (arc ACB ) = m (arc CBD ) ….(1) But m ( arc ACB ) = m ( arc AC ) + m ( arc CB ) …..(2) and m (arc CBD ) = m ( arc CB ) + m (arc BD ) ....(Arc addition postulate ) ....(3) From (1 , (2) and (3) , we get m (arc AC + m (arc CB ) = m (arc CB ) + m (arc BD ) `:. ` m (arc AC ) = m ( arc BD ) `:. ` arc `~=`` arc BD. |
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