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In the figure, BL and CM are the medians of ABC, right angled at A. Prove that 4(BL2+ CM2) = 5 BC2. (refer the figure) guys please answer about this question I don't know how to solve this question so please answer this and those who will answer this in 5 minutes he or she will be counted by me as a brainliest |
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Answer» in TRINGLE BLA by Pythagoras theorem AB2 +AL2=BL2 butAL=1/2 AC AB2+(1/2AC)2=BL2 AB2+1/4AC2=BL2 multipleying both of side by 4 we get 4AB2+AC 2=4BL2 ....(1) now in tringle MAC by Pythagoras theorem AC2 + AM2=CM2 but AM =1/2AB AC2 +(1/2AB)=CM2 AC2 + 1/4 AB =CM2 multipleying both side by 4 we get 4AC2+AB2=4CM2.....(2) ADDING 1 and 2 4AB2 +AC2=4BL2 4AC2 +AB2=4CM2 4(CM2+BL2)=AB2 + AC2+ 4AB2 +4AC2 but AB2 +AC2=BC2 therefore 4(BL2 +CM2)= BC2 + 4BC2 hence 4(BL2 +CM2)=5BC2 please mark me as a brainlist |
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