In the figure AD = 7, CD = 8, BD = 5, ∠ADP = 50° then find ADB ?If

1.	In the figure AD = 7, CD = 8, BD = 5, ∠ADP = 50° then find ADB ?If sin 50 = AP/..... find APCalculate the area of triangle ACD
Answer» ∠ADB = 180 - 50 = 130 sin50 = \(\frac{AP}{AD}=\frac{AP}{7}\) ∴ AP = 7 x sin50 = 7 x 0.7660 = 5.362 Area of ∆ACD = \(\frac{1}{2}\,CD\times AP\) = \(\frac{1}{2}\) x 8 x 5.362 = 21.448

In the figure AD = 7, CD = 8, BD = 5, ∠ADP = 50° then find ADB ?If sin 50 = AP/..... find APCalculate the area of triangle ACD

Answer»

∠ADB = 180 - 50 = 130

sin50 = \(\frac{AP}{AD}=\frac{AP}{7}\)

∴ AP = 7 x sin50 = 7 x 0.7660 = 5.362

Area of ∆ACD = \(\frac{1}{2}\,CD\times AP\)

= \(\frac{1}{2}\) x 8 x 5.362 = 21.448

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In the figure AD = 7, CD = 8, BD = 5, ∠ADP = 50° then find ADB ?If sin 50 = AP/..... find APCalculate the area of triangle ACD

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