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In the figure above, `bar(PQ) and bar(RS)` are parallel. `bar(AC)` is transversal of `bar(PQ) and bar(RS)`. If `angle(ACP)=5x-70^(@) and angleBDR=4x+70^(@)`, then find the value of x. |
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Answer» Given that, `bar(PQ)"//"bar(RS) and bar(AB)` is a transversal. Aslo given, `angleACP=5x-70^(@) and angleBDR=4x+70^(@)`. `angleACP+angleBDR=180^(@)` (`:.` Exterior angles on the same side of the transversal.) `implies 5x-70^(@)+4x70^(@)=180^(@)` `implies 9x=180^(@)implies x=20^(@)` |
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