In the figure, ABCD and AEFD are two parallelograms. Prove that (i)PE=FQ(ii)ar(△APE):ar(△PFA)=ar(△QFD):ar(△PFD)(iii)ar(△PEA)=ar(△QFD).

In the figure, ABCD and AEFD are two parallelograms. Prove that (i)PE=

1.	In the figure, ABCD and AEFD are two parallelograms. Prove that (i)PE=FQ(ii)ar(△APE):ar(△PFA)=ar(△QFD):ar(△PFD)(iii)ar(△PEA)=ar(△QFD).
Answer» In the figure, ABCD and AEFD are two parallelograms. Prove that $(i) P E = F Q (i i) a r (△ A P E) : a r (△ P F A) = a r (△ Q F D) : a r (△ P F D) (i i i) a r (△ P E A) = a r (△ Q F D) .$