1.

In the figure AB is the diameter of the circle. CD = 10 cm. BC is 15 cm less than Ac. Find AB?

Answer»

AC x CB = CD2

AC = x

x(x-15) = 102

x2 - 15x = 100

\(x^2-15x+\frac{225}{4}=100+\frac{225}{4}\)

\((x-\frac{15}{2})^2=\frac{625}{4},x-\frac{15}{2}=\frac{25}{2}\)

\(x=\frac{25}{2}+\frac{15}{2},\)

∴ AB = 20 + 5 = 25 cm



Discussion

No Comment Found

Related InterviewSolutions