In the figure, AB = AC and CP || BA and AP is the bisector of exterior ∠CAD of ΔABC. Prove that (i) ∠PAC=∠BCA(ii) ABCP is a parallelogram.

In the figure, AB = AC and CP || BA and AP is the bisector of exterior

1.	In the figure, AB = AC and CP \|\| BA and AP is the bisector of exterior ∠CAD of ΔABC. Prove that (i) ∠PAC=∠BCA(ii) ABCP is a parallelogram.
Answer» In the figure, AB = AC and CP \|\| BA and AP is the bisector of exterior $∠ C A D o f Δ A B C$ . Prove that (i) $∠ P A C = ∠ B C A$ (ii) ABCP is a parallelogram.