In the figure, a semicircle with its diameter on the hypotenuse of a

1.	In the figure, a semicircle with its diameter on the hypotenuse of a right angled triangle is shown touching the remaining sides of a triangle. The parts of the hypotenuse made by the centre of the semicircle have lengths 15 cm and 20 cm respectively. Find the radius of the semicircle. (Construction : Join OD and OE)
Answer» ong>Step-by-step explanation: Let the length shown in above diagram be T. The power of CIRCLE T 2 =(15−R)(15+R) From similar triangles (radius / hypotenuse) of right SIDE right angled triangle = R T = 20 15 = 4 3 Solving R=12 T=9 Arc length in quarter circle = 2 πR = 2 π.12 =6π. *Hope* *this will* *HELP you* *MARK me* *as brilliant*

In the figure, a semicircle with its diameter on the hypotenuse of a right angled triangle is shown touching the remaining sides of a triangle. The parts of the hypotenuse made by the centre of the semicircle have lengths 15 cm and 20 cm respectively. Find the radius of the semicircle. (Construction : Join OD and OE)

Answer»

ong>Step-by-step explanation:

Let the length shown in above diagram be T.

The power of CIRCLE T

=(15−R)(15+R)

From similar triangles (radius / hypotenuse) of right SIDE right angled

triangle =

Solving R=12 T=9

Arc length in quarter circle =

πR

π.12

=6π.

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