In the figure

1.	In the figure
Answer» PROPERTY : Angles subtended by a chord/ARC on same side of a circle at circumference are same. now arc BC subtends angles CAB and CDB at circumference on same side. so < CDB = < CAB < D = 34° similarly arc AD subtends angles B and C at circumference so B = C = 54° remaining angle APC = DPB so ∆ APC ~ ∆ DPB thus PA/PD = PC/PB PB = PC x PD/PA = 4 x 6/8 = 3 AB = PA + PB = 8 + 3 = 11

Answer»

PROPERTY :

Angles subtended by a chord/ARC on same side of a circle at circumference are same.

now

arc BC subtends angles CAB and CDB at circumference on same side.

< CDB = < CAB

< D = 34°

similarly arc AD subtends angles B and C at circumference

B = C = 54°

remaining angle

APC = DPB

so ∆ APC ~ ∆ DPB

thus

PA/PD = PC/PB

PB = PC x PD/PA

= 4 x 6/8

= 3

AB = PA + PB

= 8 + 3

= 11

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