1.

In the Fig, shown below with what angular speed 'omega' must 'm' with a radius 'r' rotate on a frictionless table so that 'M' does not move ? (b) If m = 1.0 kg, M = 10.0 kg and r = 0.5 m, find omega.

Answer»

Solution :(a) Tension in the STRING = Weight of the hanging mass M.
The tension in the string supplies the required CENTRIPETAL force to the body of mass m to revolve in a circular orbit of radius r.

`T=mr OMEGA^(2)`
`therefore mr omega^(2)=Mg`
ANGULAR speed,
`omega = sqrt((Mg)/(mr))=sqrt((10xx9.8)/(1xx0.5))=sqrt(196)=14 rad s^(-1)`.


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