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In the expression of `(1+x+x^(3)+x^(4))^(10)`, the coefficient of `x^(4)` is k then number of prime divisors of k is equal to |
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Answer» Correct Answer - 3 `(1+x+x^(3)+x^(4))^(10)=(1+x)^(10)(1+x^(3))^(10)` `k=(1+^(10)C_(1)x+^(10)C_(3).x^(2)+^(10)C_(4).x^(3)+^(10)C_(2).x^(4)..)(1+^(10)C_(1).x^(3)+^(10)C_(2).x^(6)+….)` `implies"coefficient" of x^(4)=^(10)C_(1).^(10)C_(1)+^(10)C_(4)=310` |
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