1.

In the expansion of (x2– 2x)10 , the coefficient of x16 is(A) -1680(B) 1680(C) 3360(D) 6720

Answer»

(C) 3360

(x2 – 2x)10 = x10 (x – 2)10

To get the coefficient of x16 in (x – 2x)10,

we need to check coefficient of x6 in (x – 2)10

∴ Required coefficient = 10C6 (-2)4

= 210 × 16

= 3360



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