In the estimation of Sulphur by Carius method, 0.468 g of an organic S

1.	In the estimation of Sulphur by Carius method, 0.468 g of an organic Sulphur compound afforded 0.668 g of barium sulphate. Find out the percentage of Sulphur in the given compound.
Answer» Total mass of organic compound = 0.468 Mass of barium sulphate formed = 0.668 g 1 mol of BaSO₄ = 233 g of BaSO₄ contains 32 g of Sulphur Thus, 0.668 g of BaSO₄ solution contains = \(\frac{32\times0.668}{233}\) g of Sulphur = 0.0917 g of Sulphur Therefore, Percentage of Sulphur, = \(\frac{0.0197}{0.468}\) × 100 = 19.59% Hence, the percentage of Sulphur in the given compound is 19.59%

In the estimation of Sulphur by Carius method, 0.468 g of an organic Sulphur compound afforded 0.668 g of barium sulphate. Find out the percentage of Sulphur in the given compound.

Answer»

Total mass of organic compound = 0.468

Mass of barium sulphate formed = 0.668 g

1 mol of BaSO₄ = 233 g of BaSO₄ contains 32 g of Sulphur

Thus, 0.668 g of BaSO₄ solution contains

= \(\frac{32\times0.668}{233}\) g of Sulphur

= 0.0917 g of Sulphur

Therefore, Percentage of Sulphur,

= \(\frac{0.0197}{0.468}\) × 100

= 19.59%

Hence, the percentage of Sulphur in the given compound is 19.59%