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In the ellipse x^2 ÷a^2 + y^2÷b^2 = 1 y=x and 3y+2x=0 are a pair of conjugate diameters then the eccentricity of the ellipse is

Answer» In the ellipse x^2 ÷a^2 + y^2÷b^2 = 1 y=x and 3y+2x=0 are a pair of conjugate diameters then the eccentricity of the ellipse is


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