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In the dimension of a physical quantities are given by `M^(0)L^(1)T^(0)` , then the physical quantity will beA. pressure if `a=1, b= -1, c= -2`B. velocity if `a=1, b=0, c= -1`C. acceleration if `a=1, b=1, c= -2`D. force if `a=0, b= -1, c= -2` |
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Answer» Correct Answer - A (i) Dimension of velocity `= [M_(0)L_(1)T_(-1)]` Here , `a=0,b=1,c=-1` (ii) Dimensions of acceleration `= [M_(0)L_(1)T_(-2)]` Here `a = 0,b =1,c= -2` (iii) Dimensions of forcwe `-[M_(1)L_(1)T_(-2)]` Here, `a = 1,b=1,T = -2` (iv) Dimensions of pressure `=[M_(1)L_(-1)T_(-2)]` `:.` Here, `a = 1,b = -1,c=-2` `:.` The physical quantity is pressure. |
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