1.

In the diagram the connected masses are pulled by a force of 400N. Find the acceleration of the system. Find the value of tension T.​

Answer»

ong>Given that,

  • Force APPLIED on the system = 400 N.
  • Tension on the STRING = ?
  • Masses in the system = 100kg, 200kg & 100kg.

Let's calculate acceleration,

ACCORDING to the Newton second LAW of motion,

F = ma

where,

  • F = 400 N
  • a = ?

Mass = 100 kg + 200 kg + 100 kg = 400 kg.

Substitute the values in the above equation,

  • 400 N = 400 kg × a
  • a = 400 N / 400 kg
  • a = 1 m/s^2.

Therefore, the acceleration is 1 m/s^2.

Let's calculate the Tension on thr string,

Here, T pulls only two masses (i.e.. 100kg & 200kg )

  • Here, mass = 100 kg + 200 kg = 300 kg.
  • Acceleration = 1 m/s^2.
  • Force = ? ( here force is tension on thr string )

According to Newton's second law of motion,

  • First = ma
  • F = 300 kg × 1 m/s^2
  • F = 300 N.

Therefore, the tension on the string is 300N.

Hope this helps you.

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