In the cricket game, a batsman strikes the ball such that it moves with the speed 30ms^(-1) at an angle 30^(@) with the horizontal as shown in the figure. The boundary line of the cricket ground is located at a distance of 75 m from the batsman? Will the ball go for a six? (Neglect the air resistance and take acceleration due to gravity g=10ms^(-2).

In the cricket game, a batsman strikes the ball such that it moves wit

1.	In the cricket game, a batsman strikes the ball such that it moves with the speed 30ms^(-1) at an angle 30^(@) with the horizontal as shown in the figure. The boundary line of the cricket ground is located at a distance of 75 m from the batsman? Will the ball go for a six? (Neglect the air resistance and take acceleration due to gravity g=10ms^(-2).
Answer» Solution :The motion of the cricket ball in air is essentially a projectile motion. As we have already seen, the range (horizontal distance) of the projectile motion is given by `R=(u^(2)SIN2THETA)/(g)` The INITIAL speed `u=30ms^(-1)` The PROJECTION angle `theta=30^(@)` The horizontal distance travelled by the cricket ball `R=((30)^(2)xxsin60^(@))/(10)=(900xx(sqrt3)/(2))/(10)=77.94m` This distance is greater than the distance of the BOUNDARY LINE. Hence the ball will cross this line and go for a six.