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In the circuit the rms value of voltage across the capacitor C, inductor L and resister `R_(1)` are respectively `5sqrt(5V)`, 10 V and 5V. Then the peak voltage a cross `R_(2)` is A. 7VB. 10VC. 15VD. `5sqrt(2)V` |
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Answer» Correct Answer - B `V_(C)^(2)+V_(R)^(2)=V_(L_^(2)+V_(R)^(2):` `125+25=100+V_(R_(2))^(2)rArrV_(R_(2))=5sqrt(2V)`, `(V_(R_(2)))_("peak")=(5sqrt(2))xxsqrt(2)` |
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