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In the circuit shown, the symbols have their usual meanings. The cell has emf `varepsilon.X` is initially joined to `Y` for a long time. Then `X` is joined to `Z`. The maximum charge on `C` at any later time will beA. `(varepsilon)/(Rsqrt(LC))`B. `(varepsilonR)/(2sqrt(LC))`C. `(varepsilonsqrt(LC))/(2R)`D. `(varepsilonsqrt(LC))/(R)` |
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Answer» Correct Answer - D |
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