1.

In the circuit shown in the figure, if both the lamps L_(1) and L_(2) are identical

Answer»

Their brightness will be same
`L_(2)` will be brighter than `L_(1)`
As FREQUENCY of SUPPLY voltage is increased brightness of `L_(1)` will INCREASE and that of `L_(2)` will decrease
Only `L_(2)` will glow because the capacitor has infinite resistance.

Solution :`X_(C)=(1)/(omegaC)=(1)/(2pi(50)(500xx10^(-6)))=(20)/(pi)OMEGA`
`X=omegaL=2pi(50)(10xx10^(-3))=piOmega`
`X_(C)gtX_(L)`


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