1.

In the circuit shown in the figure .A. current passing through `2Omega` resistance is zero.B. current passing through `4Omega` resistance is `5A`C. current passing through `5Omega` resistance is 4A.D. potential difference across `2Omega` resistance is zero.

Answer» Correct Answer - A::B::C::D
a., b., c., d.
`2Omega` resistance will be short-circuited as potential drop across
it is 0 also `4Omega` and `5Omega` are in parallel.
`1/R = (4+5)/(4xx5) = 9/20`
`I = 20/20 xx 9 = 9A rArr I_1 xx 4 = (9-I_1) xx 5`
`I_1 = 5A, I-I_1 = 4A` .


Discussion

No Comment Found

Related InterviewSolutions