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In the circuit shown in figure find the potentials of `A,B,C` and `D` and the current through `1Omega` and `2Omega` resistance. |
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Answer» Correct Answer - A::B::C::D `V_A=0V` (as it is earthed) `V_C-V_A=5V` `:. V_C=5V` `V_B-V_A=2V` `:. V_B=2V` `V_D-V_C=10V` `:. V_D=10+V_C=15V` `i_(2) Omega = (V_(C ) - V_(B))/(1) = 3A` from `C` to `B` as `V_(C ) gt V_(B)` `i_(1Omega)=(V_C-V_B)/2=7.5A` from `C` to `B` is `V_CgtV_B` `i_(2Omega)=(V_D-V_A)` |
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