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In the circuit shown below, the power developed in `6Omega` resistor is 6 watt. The power in watts developed in the `4Omega` resistor is A. 16B. 9C. 6D. 4 |
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Answer» Correct Answer - 2 Power `P=(V^(2))/(R)` `therefore (P_(1))/(P_(1))=(R_(2))/(R_(1))` or `(6)/(P_(2))=(4)/(6)` or `P_(2)=9` watt. |
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