1.

In the circuit shown below, the power developed in `6Omega` resistor is 6 watt. The power in watts developed in the `4Omega` resistor is A. 16B. 9C. 6D. 4

Answer» Correct Answer - 2
Power `P=(V^(2))/(R)`
`therefore (P_(1))/(P_(1))=(R_(2))/(R_(1))` or `(6)/(P_(2))=(4)/(6)`
or `P_(2)=9` watt.


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