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In the circuit shown below, the key K is closed at t = 0. The current through the battery is A. `(VR_(1)R_(2))/(sqrt(R_(1)^(2)+R_(2)^(2))) at t=0 and (V)/(R^(2)) at t=oo`B. `(V)/(R^(2)) at t=0 and (V(R_(1)+R_(2)))/(R_(1)R_(2)) at t=oo`C. `(V)/(R^(2)) at t=0 and (VR_(1)R_(2))/(sqrt(R_(1)^(2)+R_(2)^(2))) at t=oo`D. `(v(R_(1)+R_(2)))/(R_(1)R_(2)) at t=0 and (V)/(R_2) at t=oo` |
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Answer» Correct Answer - B (c) At t-0, no current will flow through L and `(R_(1))` `:. Current through battery `(V)/(R^2)` At `t=(oo)`, effective resistnace, (R_eff)=(R_(1)R_(2))/(R_(1)+R_(2))` `:. Current through battery `(V)/R_(eff))=(V(R_(1)=R_(2))/(R_(1)R_(2))`. |
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