In the circuit `P != R, ` the reading of the galvanometer is same with switch S open or closed. Then A. `I_(R) = I_(G)`B. `I_(P) = I_(G)`C. `I_(Q) = I_(G)`D. `I_(Q) = I_(R)`

In the circuit `P != R, ` the reading of the galvanometer is same with

1.	In the circuit `P != R, ` the reading of the galvanometer is same with switch S open or closed. Then A. `I_(R) = I_(G)`B. `I_(P) = I_(G)`C. `I_(Q) = I_(G)`D. `I_(Q) = I_(R)`
Answer» Correct Answer - A (a) Reading of galvanometer remains same whether switch `S` is open or closed, hence no current will flow through the switch i.e., `R` and `G` will be in series and same current will flow through them. `I_(R) = I_(G)`.

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In the circuit `P != R, ` the reading of the galvanometer is same with switch S open or closed. Then A. `I_(R) = I_(G)`B. `I_(P) = I_(G)`C. `I_(Q) = I_(G)`D. `I_(Q) = I_(R)`

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