1.

In the circuit in figure, the current flowing `5 Omega` resistance is : A. 0.5 AB. 0.6 AC. 0.9 AD. 1.5 A

Answer» Correct Answer - B
`I_(2)=(R_(1))/(R_(1)+R_(2))I=(10)/(35)xx2.1 =(21)/(35)=(3)/(5)`
`I_(2) =0.6A`.


Discussion

No Comment Found

Related InterviewSolutions