1.

In the circuit in figure, find the amount of heat genrated when switch s is closed.

Answer»


Solution :Initial distribution of charge
Applying loop law

`5-(q)/(2) +10 -(q)/(4) = 0`
`(3q)/(4) = 15`
`q = 20muC`
FINAL distribution of charge

By closing switch only `30muC` charge
flow through BATTERY of `10V`.
`W_("battery") = 10xx 30muC = 300muJ`
`U_(3muF) = (1)/(2)CV^(2) = (1)/(2)xx3muF = (10V)^(2) = 150muJ`
Heat generated `= 300muJ - 150muJ - 150muJ`


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