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In the circuit diagram shown, initially there is no energy in the inductor and the capacitor, The switch is closed at `t = 0`. Find the current `I` as a function of time if `R=sqrt(L//C)` |
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Answer» `tau_L=L/R` and `tau_C=CR, tau_C/tau_L=(CR^2)/L=C/L.L/C=1` `:. tau_L=tau_C` `:.` From the given condition `tau_L=tau_C=tau(say)` Now, in L-R circuit `I_1=V/R(1-e^(-t//tau))` In `CR` circuit, `I_2=V/Re^(-t//tau)` `:. I=I_1+I_2=V/R=`constant. |
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