Saved Bookmarks
| 1. |
In the circuit ...................... |
|
Answer» Correct Answer - `04.5` In the circuit shown below all the currents are indicated which can be obtained by KCL at all junctions. Writing KVL equation in closed loop we have `+100-30-35-2R=0` `implies 2R=35 V=V_(R)` `implies V_(5 Omega)=7xx5=35 V` `implies V_(5 Omega)/V_(R)=1` |
|