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In the circle with centre O. AB = BC = CD and angle AOB = 40°Calculate angle AOD angle AED angle BED |
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Answer» Given : circle with centre O AB = BC = CD = DE and angle AOB = 40° To Find : ∠AOD , ∠AED , ∠BED Solution: AB = BC = CD = DE => ∠AOB = ∠BOC = ∠COD = ∠DOE ∠AOB = 40° => ∠AOB = ∠BOC = ∠COD = ∠DOE = 40° ∠AOD = ∠AOB + ∠BOC + ∠COD => ∠AOD = 40° + 40° + 40° => ∠AOD = 120° ∠AED = (1/2)∠AOD => ∠AED = (1/2) 120° => ∠AED = 60° ∠BOD = ∠BOC + ∠COD => ∠BOD = 40° + 40° => ∠BOD = 80° ∠BED = (1/2)∠BOD => ∠BED = (1/2)80° => ∠BED = 40° Learn More Find the angle in degree subtended ATTHE centre of a circle by an arc ... 2. IF A,B,C,D are four points such that angle BAC = 30 and angle ... |
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