1.

In the case of a radioisotope, the value of …….and …..are indentical in magnitude. The value is

Answer»

1/0.693
`(0.693)^(2) `
`0.693`
`(0.693)^(1//2)`

SOLUTION :`t_(1//2) = (0.693)/(LAMBDA) i.e, t_(1//2) XX lambda = 0.693`.
or `X xx x = 0.693 i.e., x^2 = 0.693 " or " x = (0.693)^(1//2)`


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