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In the below reaction. The value of y is |
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Answer» \(\underset{38\,gram}{H_3C -\overset{F\\|}{CH} -CH_2 - CH_3 } \xrightarrow{\bar oH,\Delta} \underset{Major product}{CH_3 - \underset{|\\OH}{CH} - CH_2 -CH_3} + \underset{Minor product\\(Y \, gram)}{CH_3 - CH = CH - CH_3}\) Minor product will be elemination product. Assuming all \(CH_3 -\overset{F\\|}{CH} -CH_2 - CH_3\) converted into minor product. \(\therefore\) Molecular weight of \(CH_3 -\overset{F\\|}{CH} -CH_2 - CH_3\) = 76 g/mol Molecular weight of CH3 - CH = CH - CH3 = 56 g/mol Number of moles of \(CH_3 -\overset{F\\|}{CH} -CH_2 - CH_3\) = \(\frac{38}{76}\) = 0.5 mol \(\therefore\) Number of moles of minor product will be = 0.5 mol \(\therefore\) Weight of minor product = 0.5 x 56 = 28 gm Hence, the value of y = 28 gm. |
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