1.

In the adjoining figure three coplanar lines AB, CD, EF intersect at a point O, forming angles as shown. Find the value of x , y, ,z, t.

Answer»

Answer:

             x={40}^{o}, y={40}^{o}, z={50}^{o}, t={90}^{o}

SOLUTION:

When two lines intersect, the angles that are vertically OPPOSITE will be equal

Hence \angle BOC=\angle AOD

    { 90 }^{ o }=t

\angle DOF= \angle EOC

 Z= {50}^{o}

Since AB is a STRAIGHT LINE,

\angle AOE + \angle EOC + \angle COB={180}^{o}

X + {50}^{o} + {90}^{o} = {180}^{o}

X = 180 - 140 = {40}^{o}

As x and y are opposite vertical angles, x=y={40}^{o}

THEREFORE,x={40}^{o}, y={40}^{o}, z={50}^{o}, t={90}^{o}



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