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In the adjoining figure, the diagonals AC and BD of a quadrilateral ABCD intersect at O. If BO = OD, prove that ar (△ ABC) = ar (△ ADC). |
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Answer» It is given that BO = OD From the figure we know that AO is the median of △ ABD So we get Area of △ AOD = Area of △ AOB ……. (1) We know that OC is the median of △ CBD So we get Area of △ DOC = Area of △ BOC ……. (2) By adding both the equations Area of △ AOD + Area of △ DOC = Area of △ AOB + Area of △ BOC So we get Area of △ ADC = Area of △ ABC Therefore, it is proved that ar (△ ABC) = ar (△ ADC). |
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