1.

In the adjoining figure, PQ = 24 cm, QR = 26 cm, ZPAR = 90°, PA = 6 cm and AR = 8 cm.Find ZQPR.24 cmP6 cmА90°8 cm26 cmR​

Answer»

Answer:

Step-by-step explanation:

ANSWER

Given In △PAR,∠PAR=90  

∘

 

⟹PR  

2

=PA  

2

+AR  

2

 

⟹PR=  

6  

2

+8  

2

 

​  

=  

100

​  

=10 CM

In △PQR,

PQ=24 cm,PR=10 cm,QR=26 cm

Here QR  

2

=26  

2

=676,PQ  

2

+PR  

2

=24  

2

+10  

2

=576+100=676

⟹QR  

2

=PR  

2

+PQ  

2

 

⟹∠QPR=90  

∘


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